在Java中求解方程的虛根實部和虛部可以使用復數(shù)類來實現(xiàn)。復數(shù)類的定義如下：

public class Complex {
private double real;
private double imaginary;
public Complex(double real, double imaginary) {
this.real = real;
this.imaginary = imaginary;
}
public double getReal() {
return real;
}
public double getImaginary() {
return imaginary;
}
public Complex add(Complex other) {
double r = real + other.real;
double i = imaginary + other.imaginary;
return new Complex(r, i);
}
public Complex subtract(Complex other) {
double r = real - other.real;
double i = imaginary - other.imaginary;
return new Complex(r, i);
}
public Complex multiply(Complex other) {
double r = real * other.real - imaginary * other.imaginary;
double i = real * other.imaginary + imaginary * other.real;
return new Complex(r, i);
}
public Complex divide(Complex other) {
double denominator = other.real * other.real + other.imaginary * other.imaginary;
double r = (real * other.real + imaginary * other.imaginary) / denominator;
double i = (imaginary * other.real - real * other.imaginary) / denominator;
return new Complex(r, i);
}
public double abs() {
return Math.sqrt(real * real + imaginary * imaginary);
}
public String toString() {
return "(" + real + ", " + imaginary + ")";
}
}

其中，real表示實部，imaginary表示虛部。接下來我們來求解方程的虛根實部和虛部的代碼：

public class EquationSolver {
public static void main(String[] args) {
Complex a = new Complex(2, 3);
Complex b = new Complex(4, 5);
Complex c = new Complex(6, 7);
Complex delta = b.multiply(b).subtract(a.multiply(c).multiply(new Complex(4, 0)));
if (delta.getReal() >= 0) {
Complex x1 = b.add(delta.sqrt()).divide(a.multiply(new Complex(2, 0)));
Complex x2 = b.subtract(delta.sqrt()).divide(a.multiply(new Complex(2, 0)));
System.out.println("x1 = " + x1);
System.out.println("x2 = " + x2);
} else {
Complex x1 = b.divide(a.multiply(new Complex(2, 0)));
Complex x2 = new Complex(x1.getReal(), x1.getImaginary() + Math.sqrt(-1 * delta.getReal()) / a.abs());
Complex x3 = new Complex(x1.getReal(), x1.getImaginary() - Math.sqrt(-1 * delta.getReal()) / a.abs());
System.out.println("x1 = " + x1);
System.out.println("x2 = " + x2);
System.out.println("x3 = " + x3);
}
}
}

通過上面的代碼我們可以求解出方程的虛根的實部和虛部。