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編程學(xué)到什么程度可以接私活

張吉惟2年前13瀏覽0評論

編程學(xué)到什么程度可以接私活?

""******************************************** Five program grammar notes of this robot :

1) # n[*].ros; :Invoke the operating system directly from Einstein's brain( or Newton's 、Russell's、Hawking's、Marx's、Darwin's 、Wundt's、Bill Gates');

2) #m《*》.org; : Invoke the knowledge trees or books transfer timely program;

3) #k{*}.hb;:cloning the three dimensional features of human brain evolution;

4) ∑……; : working procedure ;

5) @……; : program access ; ********************************************"" #1[AI sensor - Light quantum groups identify].ros;

#2[AI sensor- Sound and mechanical shock wave identify].ros;

#3[AI sensor - Smell and taste of the digestive system identify ].ros;

#4[AI consciousness based - Character stack].ros;

#5[AI consciousness based - Phrase meaning].ros;

#6[AI consciousness based - Essay meaning].ros;

#7[AI programmed algorithm -Brain psychology].ros;

#8[AI brain psychology - Philosophy].ros;

#9[AI philosophy - Natural science].ros;

#10[AI philosophy - Sociology].ros;

#11[AI - Robot behaviour specification].ros;

#12《Sociology - Psychology》.org;

#13《Psychology - Theology》.org;

#-1{"輝歌49" - Thinking model}.hb;

#-2{"輝歌49" - Memory unit}.hb;

#-3{"輝歌49" - Thinking speed}.hb;

∑ S(L)=@#-1.hb; ""feature brain""

∑ M(t)=@#-2.hb; ""feature memory""

∑ V(M(t)&S(L))=@#-3.hb; ""feature speed""

∑ N=@(L+>11#).org; ""difficulty of question""

∑ A=@V(S(L)&M(t))&@N; ""answer""

∑ The answer:@"輝歌49"&@A:

對計算機編程語言很熟練,達到了具有八九玄功,變化自如的地步,同時應(yīng)具備哲理的思考能力。比如道家哲理也是應(yīng)當做基本素質(zhì)。這樣才能接編程私活,可參考以下道家哲理。

道法規(guī)律如表1,先一個太極分身變兩個儀,再分身變宇稱四象,再分身變八卦,再映變八個二進制,再縮變五行屬性,再映變五個科學(xué)相生相克分類,再縮變?nèi)齻€科學(xué)屬性進入三界,至此完成天干36變;經(jīng)過36變的物體具有人類意識,如欲進入三界的人間體驗人,應(yīng)先進入人間八態(tài)進行伸變?yōu)榘藗€科學(xué)程序代表的人類,進入人間規(guī)定有兩種通道,36變基礎(chǔ)上選擇一種或兩種語言即可完成72變身,如精通"數(shù)理、動作、思考"這三眼之間的結(jié)界關(guān)系,隨意選擇兩種難度通道進入人間,那么就在八九玄功基礎(chǔ)上多一變即73變,俗稱"三眼二難神"。十天干規(guī)范36變身及72變身見周天運行見表1,在表1十天干基礎(chǔ)上加"卦名"及"程序?qū)傩?二屬性得到,表2十二地支釋義十天干周天程序?qū)傩浴?/p>

表1 十天干運行周天

表2 用地支釋義周天運行