在JavaScript中,JSON是一種常見的數(shù)據(jù)格式,它非常適合在前端和后端之間進(jìn)行數(shù)據(jù)交換。如果需要在JSON數(shù)據(jù)中找到所有的children,可以使用如下的代碼:
let data = { "name": "parent", "children": [ { "name": "child1", "children": [ { "name": "grandchild1" }, { "name": "grandchild2" } ] }, { "name": "child2", "children": [ { "name": "grandchild3" }, { "name": "grandchild4" } ] } ] }; function findChildren(obj) { let children = []; if (obj.children) { children = children.concat(obj.children); obj.children.forEach(function(child) { children = children.concat(findChildren(child)); }); } return children; } let allChildren = findChildren(data); console.log(allChildren);
以上代碼會(huì)輸出所有的children,包括nested的children。在代碼中,我們定義了一個(gè)findChildren的函數(shù),它會(huì)遞歸地遍歷每個(gè)對(duì)象,如果這個(gè)對(duì)象有children屬性,則將children屬性的值加入到children數(shù)組中,然后對(duì)children屬性的每個(gè)元素遞歸調(diào)用findChildren函數(shù),將結(jié)果合并到最終的children數(shù)組中。
上一篇css背景音樂怎么插
下一篇vue自定義換膚