Java蛇和梯子是一種常見的經典游戲。它有一個棋盤，玩家需要控制一條蛇走到終點，中途會有一些障礙物，其中包括梯子，可以幫助玩家快速到達終點。這個游戲是用Java語言編寫的，下面我們就來看一下Java蛇和梯子的代碼實現吧。

import java.util.Scanner;
import java.util.ArrayList;
public class SnakeAndLadderGame {
static int[][] board = new int[10][10];
static ArrayListladders = new ArrayList<>();
public static void main(String[] args) {
initBoard();
initLadders();
Scanner sc = new Scanner(System.in);
int player = 1;
int currPos = 0;
while (true) {
System.out.println("Player " + player + ", enter your roll: ");
int roll = sc.nextInt();
currPos += roll;
if (currPos >= 100) {
System.out.println("Player " + player + " wins!");
break;
}
currPos = checkLadder(currPos);
currPos = checkSnake(currPos);
System.out.println("Player " + player + " is at " + currPos);
if (roll != 6) {
player = (player == 1) ? 2 : 1;
}
}
}
public static void initBoard() {
int counter = 100;
for (int i = 0; i< 10; i++) {
for (int j = 0; j< 10; j++) {
board[i][j] = counter;
counter--;
}
}
}
public static void initLadders() {
ladders.add(14);
ladders.add(31);
ladders.add(42);
ladders.add(69);
ladders.add(84);
}
public static int checkLadder(int currPos) {
int newPos = currPos;
for (int i = 0; i< ladders.size(); i++) {
if (currPos == ladders.get(i)) {
newPos = (100 - ladders.get(i+1));
}
}
return newPos;
}
public static int checkSnake(int currPos) {
int newPos = currPos;
if (currPos == 17) {
newPos = 7;
} else if (currPos == 54) {
newPos = 34;
} else if (currPos == 62) {
newPos = 19;
} else if (currPos == 64) {
newPos = 60;
} else if (currPos == 87) {
newPos = 36;
} else if (currPos == 93) {
newPos = 73;
} else if (currPos == 95) {
newPos = 75;
} else if (currPos == 98) {
newPos = 79;
}
return newPos;
}
}