ExtJS是一個強大的JavaScript框架，可以幫助開發人員創建功能強大而且易于使用的Web應用程序。其中一個重要的功能就是處理復雜的JSON對象。下面是一些如何使用ExtJS處理復雜JSON對象的示例：

var myData = {
"users": [
{
"name": "John",
"age": 25,
"email": "john@example.com",
"address": {
"street": "123 Main St",
"city": "New York",
"state": "NY",
"zip": "11111"
}
},
{
"name": "Jane",
"age": 30,
"email": "jane@example.com",
"address": {
"street": "456 Oak Ave",
"city": "Los Angeles",
"state": "CA",
"zip": "22222"
}
}
]
};
//使用ExtJS的數據模型(DatatModel)創建store
var store = new Ext.data.Store({
model: 'UserModel',
data: myData.users
});
//創建Grid面板，展示store數據
var grid = new Ext.grid.GridPanel({
renderTo: "myGrid",
store: store,
columns: [
{header: "Name", dataIndex: "name"},
{header: "Age", dataIndex: "age"},
{header: "Email", dataIndex: "email"},
{header: "Street", dataIndex: "address.street"},
{header: "City", dataIndex: "address.city"},
{header: "State", dataIndex: "address.state"},
{header: "Zip", dataIndex: "address.zip"}
]
});
//數據模型定義
Ext.define('UserModel', {
extend: 'Ext.data.Model',
fields: [
{name: 'name', type: 'string'},
{name: 'age', type: 'int'},
{name: 'email', type: 'string'},
{name: 'address', mapping: 'address.street'},
{name: 'address', mapping: 'address.city'},
{name: 'address', mapping: 'address.state'},
{name: 'address', mapping: 'address.zip'}
]
});

以上代碼展示了如何使用ExtJS處理一個復雜的JSON對象并展示在Grid面板中。其中數據模型UserModel中定義了數據類型和數據的映射關系。在創建store時，使用數據模型作為參數，將原始JSON對象中的users數據傳遞給store。Grid面板的列使用字段名稱或者字段映射來展示數據。