在C語言中如何拼接JSON格式的字符串呢？

我們可以使用一個(gè)結(jié)構(gòu)體來表示一個(gè)JSON對(duì)象。假設(shè)要構(gòu)建以下JSON格式：

{
"name": "張三",
"age": 20,
"hobby": ["籃球", "游戲"]
}

我們可以定義一個(gè)結(jié)構(gòu)體如下：

typedef struct {
char* name;
int age;
char** hobby;
int hobby_count;
} Person;

JSON字符串拼接的方法通常是通過snprintf()函數(shù)來實(shí)現(xiàn)。

拼接一個(gè)JSON對(duì)象的示例代碼如下：

void serialize_person(char* buffer, size_t buffer_size, Person* person) {
snprintf(buffer, buffer_size, "{\"name\":\"%s\",\"age\":%d,\"hobby\":[", person->name, person->age);
int i, remaining_size;
char* buffer_pointer = buffer + strlen(buffer);
for (i = 0; i< person->hobby_count; i++) {
remaining_size = buffer_size - (buffer_pointer - buffer);
snprintf(buffer_pointer, remaining_size, "\"%s\"", person->hobby[i]);
buffer_pointer += strlen(buffer_pointer);
if (i != person->hobby_count - 1) {
snprintf(buffer_pointer, remaining_size, ",");
buffer_pointer += 1;
}
}
snprintf(buffer_pointer, remaining_size, "]}");
}

我們可以調(diào)用serialize_person()函數(shù)來將一個(gè) Person 結(jié)構(gòu)體轉(zhuǎn)換為對(duì)應(yīng)的 JSON 字符串。示例代碼如下：

int main() {
Person person;
person.name = "張三";
person.age = 20;
char* hobby[2] = {"籃球", "游戲"};
person.hobby = hobby;
person.hobby_count = 2;
char buffer[1024];
serialize_person(buffer, sizeof(buffer), &person);
printf("%s\n", buffer);
return 0;
}

輸出：

{"name":"張三","age":20,"hobby":["籃球","游戲"]}

使用以上方法，我們可以輕松地在 C 語言中拼接 JSON 字符串。